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Node or mouse click position on right click event Hi, Is it possible to detect node or mouse click position on right click event? What I'm trying to do is to display some text on a floating div next to the node (eg. similar to a tooltip) when user right clicks on a node. Currently I have something like the following: function initTree() { ... myTree.setOnRightClickHandler(nodeRightClicked); ... } function nodeRightClicked() { displayText("some text", positionX, positionY); } where positionX and positionY are the X and Y 'coordinates' (of the top left corner) where the floating div will be displayed I tried to use e.clientX and e.clientY but both values are null/undefined thank you in advance Answer posted on Dec 05, 2007 02:01 If you are using latest version of dhtmlxtree, the event object accessible as second parameter of event handler myTree.setOnRightClickHandler(nodeRightClicked); function nodeRightClicked(id,ev) { //ev - event object displayText("some text", ev.clientX, ev.clientY); } Answer posted by Tom on Jul 30, 2008 03:40 I have the same problem. But your solution does not work for me. I have the latest Enterprise version of dhtmlxTree but I am getting "undefinded" for both "clientX" and "clientY" when trying your solution. What else can I check? Answer posted by Support on Jul 30, 2008 05:35 Which browser you are using? The same code works correctly with latest codebase in both IE and FF ( sample attached ) Attachments (1)
Answer posted by Tom on Jul 30, 2008 06:18 Thanks for your prompt reply. I was not very precise. Sorry for that. I am using both FF3 and IE7. I got your example working now. Of course I had to remove the ContextMenu since the right clicks interfered. But .... what I need is to get the position on a LeftClick. Your example is only working with "setOnRightClickHandler" but neither with "setOnClickHandler" nor with "setOnDblClickHandler". And I stripped my code to the basic commands. What am I doing wrong? By the way: This is what I am trying to realize: I have a form next to my tree that gets the name of the node the user clicks/selects in the tree to the left. But when the tree is kind of long I have to scroll down. So I want the form to the right to be / to jump on the same horizontal line of the node I left-clicked/selected. Thanks again Answer posted by Support on Jul 31, 2008 03:18 The onClick and onDblClick events do not provide information about exact position of click. You can a) modify source code of tree, to get such info dhtmlxtree.js, line 1633 in latest code else that.callEvent("onClick",[obj.id,lastId]); can be replaced with else that.callEvent("onClick",[obj.id,lastId,e]); In such case third parameter of event will be DOM event object. b) you can use next code to get position of item by its id var z=getAbsoluteTop(this._idpull[ID].htmlNode)-getAbsoluteTop(this.allTree); where ID - id of item |